Fun Geometry Problem with Solution #49
blog йʹ⨷ Ҩ繺 (Lemma) Ѻþ٨駵




٨ AC = BD = CD
٨



(1) BA ͡ѧش P ·∠BPC= α <=> ∠BPC=∠CBP <=> ∆BCP繠∆˹Ҩ ՠ∠Cʹ <=> CP = BC
͡ҡ ѧҠ∠ACP= α <=> ∠ACP=∠APC <=> ∆ACP繠∆˹Ҩ ՠ∠Aʹ <=> AP = AC <=> AP = BD

(2) ѧࡵҠ∆BCD ∆ACP¤ѹẺ -- (BD = AP,∠CBD=∠APC, BC = CP) => CD= AC
∴ AC = BD = CD Q.E.D.



Create Date : 16 ѹ¹ 2557
Last Update : 16 ѹ¹ 2557 0:00:31 .
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